“I bought this guide a few days ago to prepare for my interview with Oracle. Many of the questions they asked me were from this guide. I found this book absolutely great!”
A lot. There are too many variables that remain undefined to accurately answer that question. I could make assumptions like “The bus is 45 feet long” and “The bus is already filled with salami” but neither would help.
Here:
VOneSeat is volume of one seat
VIron is volume of iron used to make one seat
VSeatCloth is volume of cloth used to make one seat
VTempSeat is volume of other items used to build the seat
VActualBus is volume of actual bus with seats and other temp things inside it
VEmptyBus is volume of empty bus i.e without any seats or other temp items inside it (length*width*height)
NSeat is num of seats in the bus assuming that all seats are equal
VTempBus is volume of other items in the bus
NGolfBall is number of golf balls which can fit in a bus
The height of a school bus is about 7ft since people can easily stand in it. The width is about the same… If you’d lie along the breadth, you’d just fit. Finally the length is about 30ft. 7*7*30 would give you the volume. Now, for the ease of calculation, assume the ball to be a cube rather than a sphere. You have the volume as (1/12)^3. Then we divide… This should give a pretty close answer even though we have not considered the volume of chairs. This is because we have probably overcompensated in the dimesons a bit and also due to the fact that balls will tend to occupy lesser space as compared to cubes.
It doesn’t matter how many golf balls fit in the school bus. The point of this being in an interview is to see how many variables you can think of. Take charge and ask questions to show that you are thinking of all the possibilities, but do it in a good, social way with the people interviewing you. =)
This answer is pretty much straight from SMU’s Cox School of Business Career Counselor where they continually help and coach people with interviews…
Arrange 3 balls such that they form a triangle and then place a ball above and underneath the space that is created by the 3 ball arrangement and continue till you fill the bus.
I suppose you need to describe to the interviewer all the scenarios : Possiblity of the bus as a empty cuboid, or a bus with seats in it as well the rods for holding and drivers seat as well. This also includes whether its a double layered or the one like a shuttle. there can be various such scenarios. Now you proceeed with… How many people should be there in that bus when the it is suposed to be filled with golf balls. (if there has to be any). And the approximate number should be followed by… the volume of the bus (in all cases)/ the spherical volume of the golf ball. (Assuming that all golf balls that are supposed to be filled are of the same size.)
The question is basically to determine how much scenarios can you think of in any given case and given situation. And how You can convice the interviewer with your approximated figure.
we can reasonably assume that the shape of bus is rectangular for calculation puproses:
lets say L*B*H of bus is 360″*120″*96″.
and L*B*H required to store a ball perfectly in a rectangular box is 2″*2″*2″, then we can approx. store
180*60*48 balls in a bus.
You can fit lot many Golf balls. But there will always be some space left when you place the balls one beside other. Since the balls are spherical and we need to fill a cuboid, there will always be some space left for AIR. Hence you cannot fill the bus completely with golf balls! It would’ve been possible if we could crush few balls to fill the gap.
I guess the intent here is how many spheres (balls) can be fit in an cuboid (Bus)…
Since, one cannot utilize the interleaved spaces when spheres are placed in a cuboid, a sphere should also be treated as smaller cuboid and hence the answer should be …
= round ( (L*B*H)/(D*D*D) )
where L, B, H are Bus dimensions
and D is the Diameter of the Golf ball
A lot. There are too many variables that remain undefined to accurately answer that question. I could make assumptions like “The bus is 45 feet long” and “The bus is already filled with salami” but neither would help.
One.
It takes many golf balls to FILL the school bus
About 500,000, assuming the bus is 50 balls high, 50 balls wide, and 200 balls long
All golf balls can fit in a school bus.
Its depends upon the size and capacity of the bus.
VOneSeat = VIron + VSeatCloth + VTempSeat;
VActualBus = VEmptyBus-(VOneSeat*NSeat) - VTempBus;
NGolfBall = VActualBus/VGolfBall ;
Here:
VOneSeat is volume of one seat
VIron is volume of iron used to make one seat
VSeatCloth is volume of cloth used to make one seat
VTempSeat is volume of other items used to build the seat
VActualBus is volume of actual bus with seats and other temp things inside it
VEmptyBus is volume of empty bus i.e without any seats or other temp items inside it (length*width*height)
NSeat is num of seats in the bus assuming that all seats are equal
VTempBus is volume of other items in the bus
NGolfBall is number of golf balls which can fit in a bus
it depends on the size of the bus
What is the volume of a school bus?
1 to all golf balls ever manufactured will fit. school bus volume is not stated/restricted.
The height of a school bus is about 7ft since people can easily stand in it. The width is about the same… If you’d lie along the breadth, you’d just fit. Finally the length is about 30ft. 7*7*30 would give you the volume. Now, for the ease of calculation, assume the ball to be a cube rather than a sphere. You have the volume as (1/12)^3. Then we divide… This should give a pretty close answer even though we have not considered the volume of chairs. This is because we have probably overcompensated in the dimesons a bit and also due to the fact that balls will tend to occupy lesser space as compared to cubes.
Is the bus empty or does it have students in it?
It doesn’t matter how many golf balls fit in the school bus. The point of this being in an interview is to see how many variables you can think of. Take charge and ask questions to show that you are thinking of all the possibilities, but do it in a good, social way with the people interviewing you. =)
This answer is pretty much straight from SMU’s Cox School of Business Career Counselor where they continually help and coach people with interviews…
Well there is a mathematical answer:
0.64 * volume of bus/ volume of golf ball.
This is how you do it.
Arrange 3 balls such that they form a triangle and then place a ball above and underneath the space that is created by the 3 ball arrangement and continue till you fill the bus.
Look up on sphere packing
I suppose you need to describe to the interviewer all the scenarios : Possiblity of the bus as a empty cuboid, or a bus with seats in it as well the rods for holding and drivers seat as well. This also includes whether its a double layered or the one like a shuttle. there can be various such scenarios. Now you proceeed with… How many people should be there in that bus when the it is suposed to be filled with golf balls. (if there has to be any). And the approximate number should be followed by… the volume of the bus (in all cases)/ the spherical volume of the golf ball. (Assuming that all golf balls that are supposed to be filled are of the same size.)
The question is basically to determine how much scenarios can you think of in any given case and given situation. And how You can convice the interviewer with your approximated figure.
Thanks
BS
19,456,347. you are welcome to verify the same!
Every golf ball can fit inside a school bus.
the Bus capacity is approx. 10*7*67=46900
Gulf Ball size is approx.1.5
so 1.5*46900=70350 ball
am i being hired at Google
we can reasonably assume that the shape of bus is rectangular for calculation puproses:
lets say L*B*H of bus is 360″*120″*96″.
and L*B*H required to store a ball perfectly in a rectangular box is 2″*2″*2″, then we can approx. store
180*60*48 balls in a bus.
You can fit lot many Golf balls. But there will always be some space left when you place the balls one beside other. Since the balls are spherical and we need to fill a cuboid, there will always be some space left for AIR. Hence you cannot fill the bus completely with golf balls! It would’ve been possible if we could crush few balls to fill the gap.
I guess the intent here is how many spheres (balls) can be fit in an cuboid (Bus)…
Since, one cannot utilize the interleaved spaces when spheres are placed in a cuboid, a sphere should also be treated as smaller cuboid and hence the answer should be …
= round ( (L*B*H)/(D*D*D) )
where L, B, H are Bus dimensions
and D is the Diameter of the Golf ball
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