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I guess that the :: operator is not an operator in the usual way, because it takes names as parameters and not values… (see Stroustroup for more details)
:: is not an operator. It is only a syntactic construction to separate keywords, and is only understood by the compiler. :: is not evaluated at runtime.
I guess that the :: operator is not an operator in the usual way, because it takes names as parameters and not values… (see Stroustroup for more details)
:: is not an operator. It is only a syntactic construction to separate keywords, and is only understood by the compiler. :: is not evaluated at runtime.
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