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Top 100 Interview Questions & Answers in a convenient and easy to read book!

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  1. Submitted By: me — November 12, 2008
    +1 votes
      + -

    I guess that the :: operator is not an operator in the usual way, because it takes names as parameters and not values… (see Stroustroup for more details)

  2. Submitted By: anonymous — January 10, 2009
    +6 votes
      + -

    :: is not an operator. It is only a syntactic construction to separate keywords, and is only understood by the compiler. :: is not evaluated at runtime.

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