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The time is 3:15, i.e. 25% of the time between 3 and 4 has passed. The hour-hand should, by simple mechanical logic, have moved 25% of its total distance between 3 and 4.
The total angle the hand covers is 360%, so the angle covered between 3 and 4 should be 360/12 = 30 degrees.
The minute hand is smack on 3, and the hour hand is a quarter of 30 degrees further on. The angle made between them is thus 30*1/4 = 7.5 degrees.
The hour hand will cover 360 per 12 hours -> 30 degrees per hour -> 30 degrees per 60 min -> 30/60 degrees per min ->30/60 *15 per 15 mins, which is 7.5 degrees
15 degrees.
from the 3′o’clock point to 6′o’clock point is 90 degrees, i.e., 6 degrees per every minute counter. thus, 3.15 is 2.5 minutes away from the 3′o’clock point (i.e, the hour hand is 25% between 3 and 4).
so simply , 6 degrees * 2.5 = 15 degree.
OR
360/60=6 degrees per every minute mark.
so 6 * 2.5 = 15 degrees
when we travel 60 minutes we complete 360 degree
so 1 min will have 6 degree.
Now lets minutes hand reaches 15 mins it has complete 25% of its distance.
So we have to find out the 25% of distance which hours hand would have covered.
that is : 5 * .25 = 1.2 mins
so our hours hand would have covered 16.2 mins.
so the angle between hours clock and minutes clock will be 1.2 * 6 = 7.2 degree… just an another appoach to solve the problem
@Gork: That’s one smart but DUMB answer. When they’ve explicitly mentioned “hour” and “minute” “hands”, where does the question of digital clock come in.
Ans is
((15*5)/60)*(360/60)
=7.5 degrees
At 3 o’clock the hour hand will exactly point to 3 and minute hand to 12.
When minute hand moves by 360 degrees hour hand moves through 30 dgrs. So when minute hand will reach 3 hour hand will move ahead by (30/360)*90 = 7.5 degrees.
So acute angle between dese two hands is 7.5 dgrs
and obtuse angle 352.5 dgrs
Proof..
1) A clock is divided by 360 degrees and 12 hours; therefore, 30 degrees per hour.
2) The minute hand would be at the 3, and the hour 1/4 of the way to 4 (30 degrees between 3 and 4); therefore 1/4*30 = 7.5.
Answer is 7.5 degree. Formula I applied was 360:90::90:?
The time is 3:15, i.e. 25% of the time between 3 and 4 has passed. The hour-hand should, by simple mechanical logic, have moved 25% of its total distance between 3 and 4.
The total angle the hand covers is 360%, so the angle covered between 3 and 4 should be 360/12 = 30 degrees.
The minute hand is smack on 3, and the hour hand is a quarter of 30 degrees further on. The angle made between them is thus 30*1/4 = 7.5 degrees.
The hour hand will cover 360 per 12 hours -> 30 degrees per hour -> 30 degrees per 60 min -> 30/60 degrees per min ->30/60 *15 per 15 mins, which is 7.5 degrees
15 degrees.
from the 3′o’clock point to 6′o’clock point is 90 degrees, i.e., 6 degrees per every minute counter. thus, 3.15 is 2.5 minutes away from the 3′o’clock point (i.e, the hour hand is 25% between 3 and 4).
so simply , 6 degrees * 2.5 = 15 degree.
OR
360/60=6 degrees per every minute mark.
so 6 * 2.5 = 15 degrees
Okies this is what i think :
when we travel 60 minutes we complete 360 degree
so 1 min will have 6 degree.
Now lets minutes hand reaches 15 mins it has complete 25% of its distance.
just an another appoach to solve the problem
So we have to find out the 25% of distance which hours hand would have covered.
that is : 5 * .25 = 1.2 mins
so our hours hand would have covered 16.2 mins.
so the angle between hours clock and minutes clock will be 1.2 * 6 = 7.2 degree…
Answer = 7.5°
Logic:
It takes 60 min for the big hand to move from the 3 to the 4. Because it is 3:15 the big hand has only move 25% of the distance from the 3 to the 4.
A clock has 360°
5 min = 30° which is the distance between the 3 and 4
25% of 30° is the distance the big hand has moved between the 3 and 4 which = 7.5°
First of all, the clock could be two types:
1) Continously moving (Minute and hour hands move continously)
2) Discretely moving (Minute hand moves only after 60 seconds and hour hand moves only after 12 minutes)
if it is type 1 clock then the answer is 7.5 Minutes.
But if it is type 2 clock then the answer is 6 minutes. (as the hour hand moves only after every 12 minutes)
Question is irrelevant, since clock is digital.
@Gork: That’s one smart but DUMB answer. When they’ve explicitly mentioned “hour” and “minute” “hands”, where does the question of digital clock come in.
Ans is
((15*5)/60)*(360/60)
=7.5 degrees
Ans. 7.5 degrees or 352.5 degrees
My Logic:
At 3 o’clock the hour hand will exactly point to 3 and minute hand to 12.
When minute hand moves by 360 degrees hour hand moves through 30 dgrs. So when minute hand will reach 3 hour hand will move ahead by (30/360)*90 = 7.5 degrees.
So acute angle between dese two hands is 7.5 dgrs
and obtuse angle 352.5 dgrs
The answer is simply 7.5 degrees.
Proof..
1) A clock is divided by 360 degrees and 12 hours; therefore, 30 degrees per hour.
2) The minute hand would be at the 3, and the hour 1/4 of the way to 4 (30 degrees between 3 and 4); therefore 1/4*30 = 7.5.
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