Interview Questions And Answers 
-
How much does the ice in a hockey rink weigh?
10,638 Views |
(14 votes, avg: 3.86)
Loading ...
Answers »
Our Sponsors
Our Sponsors
How much does the ice in a hockey rink weigh?
10,638 Views | (14 votes, avg: 3.86)
Loading ...
I guess you need to figure out how big the rink is, and then how thick the ice is. That will give you how many cubic cenimeters of ice there is. Then you can figure how much each cubic centimeter weighs, and multiply it by the number of cubic centimeters in the rink.
total weight=area of rink* weight of ice in 1 unit square area
total weight=VOLUME of rink (area does not weigh anything)
Also note that 1cc of water is 1 gram, of course temperature and preasure affects weight. Ice is also funny in that it expands between 0 and -2 degrees celious. So I would melt the ice to a known temperature and then measure its volume as a liquid (in liters).
It weighs the same…(provided gravitational constant of the places where it is weighed is the same)
Ice doesn’t weigh anything. It floats. Obviously.
Lets make a few assumptions:
1. The length of the rink is 200 feet.
2. The width of the rink is 100 feet.
3. The depth of the rink is 1 foot.
4. The ice in the rink is ice + salt or some other additive to increase cohesion of the ice and to increase its melting point. The weight of this ice mixture is 1.5 g for each 1 cc.
From these assumptions, we have 200×100x1 cubic feet of ice = 20,000 cubic feet = 328,000 cc. The total weight of the ice rink will thus be 328,000 * 1.5 g = 492 kg. The weight of the goals will add slightly increasing the weight to approximately 500 kg.
Answer 7 is completely wrong. 20,000 cubic feet is certainly NOT 238,00 cc: 1 cubic foot = (30 cm)^3 = 27,000 cm^3.
Here are my assumptions:
)
1. Length of rink: 70 m
2. Width of rink: 30 m
3. Ice thickness: 10 cm = 0.1 m
4. Ice density: I’ll assume it to be the same as water density: 1000 kg/m^3 (it’s not, but I think it’s close enough
Ice volume:
V = 70m x 30m x 0.1m
= 210m^3
Ice weight:
W = V x density = 210m^3 x 1000 kg/m^3
= 210,000 kg
= 210 ton
Therefore, according to the assumptions the ice should weigh around 210 ton.
total weigh = quntity of water present in ice after melting.
Answer 8 is a good attempt except for the fact the density of ice is not the same density of water. it is 90% of the density of water. hence why ice floats.
so by above answer the weight is 10 times the volume visible
An ice rink is in the shape of an oval.
The oval consists of a rectangular portion in the middle and two semicircles on either side.
If the width of the rink is W and the length of the rectangular portion is L, then the total area is:
PI * (W/2)^2 + W*L
If the thickness of the ice is H, then the total volume V is given by:
V = H * W * (PI * W * L / 4 + L)
Ice has a density 90% that of water. Water weighs 1 gram per ml, so ice weighs 0.9 g/cc
So the total weight is therefore:
weight = V * 0.9 g/cc
Leave an Answer/Comment